How do you find the average rate of change for the function #s(t)=4.5t^2# on the indicated intervals [6,9]?
1 Answer
Jul 28, 2018
Explanation:
#"the average rate of change of "f(x)" in the closed interval"#
#[a,b] " is a measure of the slope of the secant line"#
#"joining the points "(a,f(a)" and "(b,f(b)#
#"average rate of change "=(f(b)-f(a))/(b-a)#
#"here "[a,b]=[6,9]#
#f(b)=f(9)=4.5(9)^2=364.5#
#f(a)=4.5(6)^2=162#
#"average rate of change "=(364.5-162)/3=67.5#
