Question

How do you find the average rate of change for the function `s(t)=4.5t^2` on the indicated intervals [6,6+h]?

Answer 1

It is `4.5*(h+12)`

Explanation:

It is

#(Δs)/(Δt)=(s(6+h)-s(6))/(6+h-6)=4.5*((6+h)^2-6^2)/(6+h-6)= 4.5/h*(36+12h+h^2-36)=4.5*((h^2+12h)/h)=4.5*(h+12)#