How do you find the average rate of change of $f (x) = 10 x^{3} + 10$ $f(x)=10x^3+10$ over the interval [1,3]?

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How do you find the average rate of change of $f (x) = 10 x^{3} + 10$ $f(x)=10x^3+10$ over the interval [1,3]?

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Answer 1 · 2016-05-07T16:36:19

The average rate of change can be found through finding $\frac{f (3) - f (1)}{3 - 1}$ $(f(3)-f(1))/(3-1)$ .

$\frac{f (3) - f (1)}{3 - 1} = \frac{(10 (3^{3}) + 10) - (10 (1^{3}) + 10)}{2} = \frac{270 - 10}{2} = 130$ $(f(3)-f(1))/(3-1)=((10(3^3)+10)-(10(1^3)+10))/2=(270-10)/2=130$

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How do you find the average rate of change of $f (x) = 10 x^{3} + 10$ $f(x)=10x^3+10$ over the interval [1,3]?

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How do you find the average rate of change of f(x)=10x3+10f(x)=10x^3+10 over the interval [1,3]?

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How do you find the average rate of change of $f (x) = 10 x^{3} + 10$ $f(x)=10x^3+10$ over the interval [1,3]?