How do you find the average rate of change of $f(x)= (3x^2-x)/2$ from (8,10)?

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Answer 1 · 2016-11-06T20:01:00

Average rate of change $= 26.5$

Use the slope formula to find average rate of change:

$m=(y_2-y_1)/(x_2-x_1)$

To use the slope formula, you need 2 points on the curve - we only have to x values, so we need to find f(8) and f(10).

$f(8)=92$
$f(10)=145$

These means are points are $(x_1,y_1)=(8,92)$ and $(x_2,y_2)=(10,145)$ .

$m = (145-92)/(10-8)$

$m=53/2$

$m=26.5$

How do you find the average rate of change of f(x)= (3x^2-x)/2f(x)= (3x^2-x)/2 from (8,10)?