How do you find the average rate of change of f(x) = 5x^2+2x-7f(x)=5x2+2x−7 over the interval [5,7]?
1 Answer
Jun 4, 2017
Explanation:
"the average rate of change of " f(x) " is"the average rate of change of f(x) is
(f(7)-f(5))/(7-5)larr(f(b)-f(a))/(b-a)to[a,b]=[5,7]f(7)−f(5)7−5←f(b)−f(a)b−a→[a,b]=[5,7]
f(7)=5(7)^2+2(7)-7=252f(7)=5(7)2+2(7)−7=252
f(5)=5(5)^2+2(5)-7=128f(5)=5(5)2+2(5)−7=128
rArr"average rate of change "=(252-128)/(7-5)=62⇒average rate of change =252−1287−5=62
