Question

How do you find the average rate of change of `y=x^2-x+1` over [0,3]?

Answer 1

The average rate of change of function `f` over interval `[a,b]` is `(f(b)-f(a))/(b-a)`

Explanation:

For `f(x) = x^2-x+1` over `[0,3]`, the average rate of change is

`(f(b)-f(a))/(b-a) = (f(3)-f(0))/(3-0)`

`= (7-1)/3 = 6/3 = 2`