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How do you find the average value of #f(x)=1/x# as x varies between #[2,3]#?

1 Answer

Dec 16, 2016

The average value of #f# on #[a,b]# is #1/(b-a)int_a^b f(x) dx#

Explanation:

#1/(3-2)int_2^3 1/x dx = ln(3/2)#

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