Question

How do you find the average value of the function for `f(x)=1+x^2, -2<=x<=2`?

Answer 1

`7/3`

Explanation:

Average value of `f` on `[a,b]` is

`1/(b-a) int_a^b f(x) dx`

So, for this question, the average value is

`1/(2-(-2)) int _-2^2 (1+x^2) dx = 7/3`