Question

How do you find the axis of symmetry and vertex point of the function: `y=1/20x^2`?

Answer 1

If there are only `x^2`'s involved, the answer is allways
`x=0and (0,0)`

Explanation:

A non-square `x` or a number in the function would displace both the axis and the vertex. The 1/20 only makes it flatter as compared to the standard `x^2`-graph.
graph{0.05x^2 [-20.44, 20.1, -4.54, 15.74]}