How do you find the center and radius of the circle $(x + 3) ^2+ (y – 2)^ 2 = 25$ ?

Question

1399 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-28T22:32:41

The center is $(-3,2)$ and the radius is $5$

Generally when you have the equation

$(x-x_o)^2+(y-y_o)^2=R^2$

that is a circle with center at $(x_o,y_o)$ and radius $R$

In our case that is $(x-(-3))^2+(y-2)^2=5^2$

How do you find the center and radius of the circle (x + 3) ^2+ (y – 2)^ 2 = 25(x + 3) ^2+ (y – 2)^ 2 = 25?