How do you find the center and radius of the circle given $x^{2} + y^{2} = 144$ $x^2+y^2=144$ ?

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Answer 1 · 2016-10-14T07:24:41

$center coordinates: (0, 0)$ $"center coordinates: "(0,0)$
$r a d i u s : 12$ $radius:12$

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$the general equation for circle is : {(x - a)}^{2} + {(y - b)}^{2} = r^{2}$ $"the general equation for circle is : "(x-a)^2+(y-b)^2=r^2$

$(a, b) : center coordinates$ $(a,b):"center coordinates"$

$r : radius$ $r:"radius"$

$a = 0; b = 0; r = \sqrt{144} = 12$ $a=0" ; "b=0" ; "r=sqrt 144=12$

$center coordinates: (0, 0)$ $"center coordinates: "(0,0)$
$r a d i u s : 12$ $radius:12$

How do you find the center and radius of the circle given x2+y2=144x^2+y^2=144?