How do you find the center and radius of the circle: ${(x - 7)}^{2} + {(y + 2)}^{2} = 25$ $(x-7)^2+(y+2)^2=25$ ?

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How do you find the center and radius of the circle: ${(x - 7)}^{2} + {(y + 2)}^{2} = 25$ $(x-7)^2+(y+2)^2=25$ ?

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Answer 1 · 2016-02-09T18:03:42

I found: center at $(7, - 2)$ $(7,-2)$ and radius $r = 5$ $r=5$ .

Explanation:

Consider the general form of the equation of the circle:
${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ $(x-h)^2+(y-k)^2=r^2$
with radius $r$ $r$ and center at $(h, k)$ $(h,k)$ in your case gives you:
$r = \sqrt{25} = 5$ $r=sqrt(25)=5$
$h = 7$ $h=7$
$k = - 2$ $k=-2$

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How do you find the center and radius of the circle: ${(x - 7)}^{2} + {(y + 2)}^{2} = 25$ $(x-7)^2+(y+2)^2=25$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you find the center and radius of the circle: (x−7)2+(y+2)2=25(x-7)^2+(y+2)^2=25?

1 Answer

Explanation:

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How do you find the center and radius of the circle: ${(x - 7)}^{2} + {(y + 2)}^{2} = 25$ $(x-7)^2+(y+2)^2=25$ ?