How do you find the center and radius of the the circle ${(x - 1)}^{2} + {(y + 1)}^{2} = 16$ $(x-1)^2 + (y+1)^2 = 16$ ?

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How do you find the center and radius of the the circle ${(x - 1)}^{2} + {(y + 1)}^{2} = 16$ $(x-1)^2 + (y+1)^2 = 16$ ?

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Answer 1 · 2018-05-03T07:32:51

Centre is (1, -1) and radius is 4

Explanation:

You must first recall that the general circle equation is
${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ $(x-h)^2 + (y-k)^2 = r^2$ with centre (h, k)
Therefore all that needs to be done is reverse the sign of the other number in the bracket (in this case -1 and 1) and take the square root of 16 (which is 4)

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How do you find the center and radius of the the circle ${(x - 1)}^{2} + {(y + 1)}^{2} = 16$ $(x-1)^2 + (y+1)^2 = 16$ ?

1 Answer

Explanation:

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How do you find the center and radius of the the circle (x−1)2+(y+1)2=16(x-1)^2 + (y+1)^2 = 16?

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Explanation:

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How do you find the center and radius of the the circle ${(x - 1)}^{2} + {(y + 1)}^{2} = 16$ $(x-1)^2 + (y+1)^2 = 16$ ?