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How do you find the center of the circle whose diameter has the endpoints P(7,2) Q(6,10)?

1 Answer

Jan 17, 2016

$(\frac{13}{2}, 6)$ $( 13/2 , 6 )$

Explanation:

Given the 2 endpoints of the diameter then the centre will be at the mid-point of these 2 points.

centre = $[\frac{1}{2} (7 + 6), \frac{1}{2} (2 + 10)] = (\frac{13}{2}, 6)$ $[1/2(7 + 6 ) , 1/2 (2 + 10 ) ] = ( 13/2 , 6 )$

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