Question

How do you find the center, vertices, and foci of an ellipse `(x+3)^2/225 + (y+8)^2/81 = 1`?

Answer 1

Explained below

Explanation:

Center is (-3, -8).

Length of the semi major axis is 15, therefore vertices would be (-18,-8) and (12, -8).

Distance of the focus from the center is c= `sqrt (a^2-b^2)`

= `sqrt (225-81)=sqrt144 =12`

Hence focii would be (-15, -8) and (9, -8)