How do you find the center, vertices, foci and asymptotes of #(x^2/16)-(y^2/9)=1#?
1 Answer
May 1, 2018
Center
Foci are
asymptotes are
Explanation:
This is standard form of the equation of a hyperbola with center
The vertices are
Foci are
vertices of a rectangle of dimensions
centre at
asymptotes are is
graph{x^2/16-y^2/9=1 [-10, 10, -5, 5]} [Ans]