How do you find the coefficient of #x^4# in the expansion of #(x+2)^8#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer Binayaka C. May 31, 2017 Co-efficient of #x^4# is #1120# Explanation: #(x+2)^8= x^8+nc_1x^7*2^1+nc_2x^6*2^2+nc_3x^5*2^3+ nc_4x^4*2^4+..............+2^8# Co-efficient of #x^4# is #nc_4*2^4 = (8!)/(4!*4!)*16=70*16=1120#[Ans] Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 22019 views around the world You can reuse this answer Creative Commons License