Question

How do you find the coordinates of the center of a circle whose equation is `(x+11)^2 +(y-13)^2=4`?

Answer 1

centre = (-11 , 13 )

Explanation:

The standard form of the equation of a circle is

`(x-a)^2 + (y-b)^2 = r^2`

where (a , b ) are the coords of the centre and r , the radius.

The equation here is `(x+11)^2 + (y-13 )^2`

By comparison with the standard form : centre = (-11 , 13)