Question

How do you find the critical points for `F(x) =xe^-x`?

Answer 1

`f(x)` is differentiable everywhere, so the critical points will simply be the solution(s) to `f'(x)=0`

Explanation:

`f'(x)=e^-x(1-x)=0`

critical point at `1-x=0` or `x=1`

hope that helped