Question

How do you find the definite integral for: `(1/x^(2))dx` for the intervals `[5, 6]`?

Answer 1

`= 1/30`

Explanation:

`int_5^6 1/x^2 dx`

`= int_5^6 d/dx (-1/x) dx`

`= (-1/x)_5^6 = (1/x)_6^5`

`= 1/5 -1/6 = 1/30`