Question

How do you find the definite integral for: `(2-x^2)dx` for the intervals [2,-1]?

Answer 1

`-3`

Explanation:

Definite integral would be

`int_2^-1 (2-x^2)dx`
`=[2x-x^3 /3]_2^-1`

`=(-2+1/3)-(4-8/3)`

`=-6+9/3`

`=-3`