Question

How do you find the derivative of `1/(x+1)`?

Answer 1

`=-1/(1+x)^(2)`

Explanation:

let's be different and write it as `d/dx (1+x)^(-1)` and use power rule and chain rule:

`d/dx (1+x)^(-1)`

`=(-1) (1+x)^(-2) d/dx (1+x)`

`=-(1+x)^(-2) (1)`

`=-1/(1+x)^(2)`