How do you find the derivative of $2 x + sin x$ $2x+ sin x$ ?

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How do you find the derivative of $2 x + sin x$ $2x+ sin x$ ?

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Answer 1 · 2016-01-22T22:11:56

$2 + cos x$ $2+cosx$

Explanation:

The derivative of this function is equal to the sum of the derivatives of each term.

That is, the derivative equals

$\frac{d}{d x} [2 x] + \frac{d}{d x} [sin x]$ $d/dx[2x]+d/dx[sinx]$

This boils down to knowing that $\frac{d}{d x} [k x] = k$ $d/dx[kx]=k$ and that $\frac{d}{d x} [sin x] = cos x$ $d/dx[sinx]=cosx$ , so the derivative of the expression is

$2 + cos x$ $2+cosx$

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How do you find the derivative of $2 x + sin x$ $2x+ sin x$ ?

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Explanation:

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