How do you find the derivative of $4 - (x^{2}) sin x$ $4-(x^2)sinx$ ?

Question

5586 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-13T15:59:50

$- 2 x sin (x) - x^{2} cos (x)$ $-2xsin(x)-x^2cos(x)$

By using the product rule
$(f(x)*g(x))'=f(x)'*g(x)+f(x)*g(x)'$

$k(x)=4-x^2sin(x)$
$k'(x)=0-((x^2)' * sin(x)+x^2*(sin(x))')$
$k'(x)=-2xsin(x)-x^2cos(x)$

How do you find the derivative of 4-(x^2)sinx4−(x2)sinx4-(x^2)sinx?