How do you find the derivative of: #arcsin x + arccos x#?

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Answer 1 · 2015-05-14T10:23:30

Since the derivative of

#y=arcsinx#

is

#y'=1/sqrt(1-x^2)#

and the derivative of

#y=arccosx#

is

#y'=-1/sqrt(1-x^2)#,

The derivative of the function is #0#.