How do you find the derivative of $cos^2 (x^2 - 3x)$ ?

Question

1667 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-27T04:38:20

$(6-4x) cos (x^2-3x) sin (x^2 -3x)$

First differentiate cosine function w.r.t $x^2-3x$ and then differentiate $x^2-3x$ w.r.t x.............. Chain rule

Derivative would be $-2cos(x^2 -3x) sin(x^2-3x) (2x-3)$

$(6-4x) cos (x^2-3x) sin (x^2 -3x)$

How do you find the derivative of cos^2 (x^2 - 3x)cos^2 (x^2 - 3x)?