How do you find the derivative of $cos^3(u)$ ?

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Answer 1 · 2015-10-11T09:44:46

$-3cos^2(u)sin(u)$

The law for deriving the power of a function is the following:

$d/{du} f^n(u) = n f^{n-1}(u) * f'(u)$ .

Of course, in your case $n=3$ , and $f'(u)=-sin(u)$ .

So, the result becomes

$d/{du} cos^3(u) = 3cos^2(u) * (-\sin(u))$

How do you find the derivative of cos^3(u)cos^3(u)?