How do you find the derivative of $cos (tan x)$ $cos(tan x)$ ?

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Answer 1 · 2016-12-27T02:44:28

Use the chain rule: $\frac{d y}{d x} cos (tan (x)) = - sin (tan (x)) \cdot {sec}^{2} (x)$ $dy/dx cos(tan(x)) = -sin(tan(x))*sec^2(x)$

The chain rule states that $dy/dx f(g(x)) = f'(g(x))*(g'(x))$

How do you find the derivative of cos(tan x)cos(tanx)cos(tan x)?