Question

How do you find the derivative of `f(x)=1/(3-2x)`?

Answer 1

`f'(x)=2/(3-2x)^2`

Explanation:

Here ,

`f(x)=1/(3-2x)=(3-2x)^-1`

Diff.w.r.t. `x` , `"using "color(blue)"chain rule :"`

`f'(x)`=`(-1)/(3-2x)^2d/(dx)(3-2x)to[becaused/(du)(u)^-1=-1(u)^-2]`

`:.f'(x)=(-1)/(3-2x)^2(-2)`

`:.f'(x)=2/(3-2x)^2`