Question

How do you find the derivative of Inverse trig function `y = sin cos(3x -2)`?

Answer 1

Use the chain rule.

Explanation:

To find the derivative of `y = sin (cos(3x -2))`, use the chain rule twice:

`dy/dx = cos(cos(3x -2))d/dx(cos(3x -2))`

`= cos(cos(3x -2))[-sin(3x-2)d/dx(3x-2)]`

`= cos(cos(3x -2))[-sin(3x-2)(3)]`

`= -3sin(3x-2)cos(cos(3x -2))`