Question

How do you find the derivative of `ln -x`?

Answer 1

`d/dx ln (-x) = 1/x`

Explanation:

as a rule `d/dx ln (f(x)) = 1/f(x) f'(x)`

here `f(x) = - x` and `f'(x) = -1` so we have

`d/dx ln (-x) = 1/(-x)*-1 = 1/x`