How do you find the derivative of $s=tan^2t$ ?

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Answer 1 · 2017-04-09T11:55:06

$(ds)/dt=2tan t sec^2 t$

$s=tan^2 x=(tan t)^2$

$(ds)/dt=2(tan t)^1 (tan t)'=2tan t sec^2 t$

I hope that this was clear.

How do you find the derivative of s=tan^2ts=tan^2t?