How do you find the derivative of $sin (cos (tan x))$ $sin (cos (tanx) )$ ?

Question

3589 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-24T01:43:44

$- cos (cos (tan x)) sin (tan x) {sec}^{2} x$ $-cos (cos(tan x))sin (tan x) sec^2x$

Use successively: If $y=f(u) and u=g(x), y'=(d/(du)f)g'.$

Here,

$(sin(cos(tan x)))'$

$cos (cos(tan x)) (cos (tan x))'$

$cos (cos(tan x)) (-sin (tan x) (tan x)'$

$cos (cos(tan x)) (-sin (tan x) sec^2x$

How do you find the derivative of sin (cos (tanx) )sin(cos(tanx))sin (cos (tanx) )?