How do you find the derivative of ${tan}^{2} (3 x)$ $tan^2(3x)$ ?

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Answer 1 · 2015-04-20T18:37:49

In this way with the chain rule:

$y'=2tan3x*1/cos^2 (3x) * 3=(6tan3x)/cos^2 (3x)$

or

$y'=2tan 3x*(1+tan^2 3x)*3=6tan3x(1+tan^2 3x)$ ,

and this is because $1/cosx^2 (3x)=1+tan^2 3x$ .

Answer 2 · 2015-04-20T18:52:28

I will be solving the problem using implicit differentiation...

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How do you find the derivative of tan^2(3x)tan2(3x)tan^2(3x)?