Question

How do you find the derivative of the function `y=arccos (e^7x)`?

Answer 1

The answer is: `y'=-7e^(7x)/sqrt(1-e^(14x))`

First of all i suppose there is a little mistake in your writing, I think you would write:

`y=arccose^(7x)`.

So, using the chain rule:

`y'=-1/(sqrt(1-(e^(7x))^2))*e^(7x)*7=-7e^(7x)/sqrt(1-e^(14x))`