How do you find the derivative of $y = 1 + x - cos x$ $y=1+x-cosx$ ?

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How do you find the derivative of $y = 1 + x - cos x$ $y=1+x-cosx$ ?

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Answer 1 · 2016-12-26T15:03:06

$\frac{d y}{d x} = 1 + sin x$ $dy/dx=1+sinx$

Explanation:

differentiate using $standard derivatives$ $color(blue)"standard derivatives"$

$Reminder$ $color(orange)"Reminder"$

$D (constant) = 0 \times \times D (x) = 1$ $D(" constant" )=0color(white)(xxxx)D(x)=1$

$and D (cos x) = - sin x$ $"and " D(cosx)=-sinx$

$y = 1 + x - cos x \Rightarrow \frac{d y}{d x} = 0 + 1 - (- sin x)$ $y=1+x-cosxrArrdy/dx=0+1-(-sinx)$

$= 1 + sin x$ $=1+sinx$

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How do you find the derivative of $y = 1 + x - cos x$ $y=1+x-cosx$ ?

1 Answer

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How do you find the derivative of y=1+x−cosxy=1+x-cosx?

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How do you find the derivative of $y = 1 + x - cos x$ $y=1+x-cosx$ ?