Question

How do you find the derivative of `y=e^x/x`?

Answer 1

You can use the Quotinet Rule where:
if `y=f(x)/g(x) -> y'=[f'(x)g(x)-f(x)g'(x)]/[g(x)]^2`

So you get:
`y'=(xe^x-1e^x)/x^2=`
`=e^x(x-1)/x^2`