Question

How do you find the derivative of `y=tan(2x)` ?

Answer 1

`dy/dx=2sec^2 2x`

Explanation:

`"differentiate using the "color(blue)"chain rule"`

`"Given "y=f(g(x))" then"`

`dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"`

`"here "y=tan2x`

`rArrdy/dx=sec^2 2x xxd/dx(2x)=2sec^2 2x`