How do you find the difference #-2-(-8)#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer smendyka Mar 6, 2018 Remember: minus a minus is a plus #-2 - (-8) => -2 + 8 => 8 - 2 => 6# Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 5163 views around the world You can reuse this answer Creative Commons License