How do you find the distance between the points with the given polar coordinates $P_1(1, pi/6)$ and $P_2(5, (3pi)/4)$ ?

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Answer 1 · 2018-07-08T11:24:42

$=>D~~5.34679$

We know that ,

$"Distance between Polar Co-ordinates:"A(r_1,theta_1)and B(r_2,theta_2)$ is

$color(red)(D=sqrt(r_1^2+r_2^2-2r_1r_2cos(theta_1-theta_2))...to(I)$

We have , $P_1(1,pi/6) and P_2(5,(3pi)/4)$ .

So , $r_1=1 , r_2=5 , theta_1=pi/6 and theta_2=(3pi)/4$

$=>theta_1-theta_2=pi/6-(3pi)/4=(2pi-9pi)/12=-(7pi)/12=-105^circ$

$=>cos(theta_1-theta_2)=cos(-105^circ)$

$=>cos(theta_1-theta_2)=cos(105^circ)to[becausecos(-theta)=costheta)$

$"Using : " color(red)((I)$ we get

$D=sqrt(1^2+5^2-2(1)(5)cos105^circ)$

$=>D=sqrt(1+25-10*cos105^circ)$

$=>D=sqrt(26-10cos105^circ)$

$=>D~~5.34679$

How do you find the distance between the points with the given polar coordinates P_1(1, pi/6)P_1(1, pi/6) and P_2(5, (3pi)/4)P_2(5, (3pi)/4)?