How do you find the equation for a circle with center is (-2,-3) and radius 3?

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Answer 1 · 2015-12-02T21:01:38

The equation for a circle with centre $(h, k)$ and radius $r$ can be written in standard form as:

$(x-h)^2+(y-k)^2 = r^2$

In our case:

$(x+2)^2+(y+3)^2 = 9$

A standard form for the equation of a circle of radius $r$ and centre $(h, k)$ is:

$(x-h)^2+(y-k)^2 = r^2$

In our case $h=-2$ , $k=-3$ and $r=3$ , so:

$(x-(-2))^2 + (y-(-3))^2 = 3^2$

or more simply:

$(x+2)^2+(y+3)^2=9$