How do you find the equation given (4, 6) and slope 3/2?

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Answer 1 · 2016-07-11T15:54:15

The equation of the line in slope-intercept form is
$y = \frac{3}{2} x$ $y=3/2x$

We can use the point-slope formula $y - y_{1} = m (x - x_{1})$ $y-y_1=m(x-x_1)$

Given the point (4,6) and the slope of $\frac{3}{2}$ $3/2$

$m = \frac{3}{2}$ $m=3/2$
$x_{1} = 4$ $x_1=4$
$y_{1} = 6$ $y_1=6$

Plug in the values and simplify

$y - 6 = \frac{3}{2} (x - 4)$ $y-6=3/2(x-4)$

Distribute the slope

$y - 6 = \frac{3}{2} x - 6$ $y-6=3/2x-6$

Use additive inverse to isolate the $y$ $y$

$y cancel(-6) cancel(+6) = 3/2x cancel(-6) cancel(+6)$

The equation of the line in slope-intercept form is
$y=3/2x$