Question

How do you find the equation of the circle given center (-2,4) and radius 6?

Answer 1

`(x+2)^2+(y-4)^2=36`

Explanation:

`(x-a)^2+(y-b)^2=r^2` where (`a,b`) is the centre and `r` is the radius.

`(x+2)^2+(y-4)^2=36`