What conic section has the equation x^2+y^2+12x+8y=48?

1 Answer
Sep 13, 2014

This is an equation for a circle. You begin by reorganizing the terms of the function so that x and x^2 are together and y and y^2 are together.

Next you will have to use the Completing the Square method.

Step 1: Reorder the terms

x^2+12x+y^2+8y=48

Step 2: Begin Completing the square

x^2+12x+y^2+8y=48

(12/2)^2=6^2=36, Value to be added to complete the square

(8/2)^2=4^2=16, Value to be added to complete the square

x^2+12x+36+y^2+8y+16=48+36+16

(x^2+12x+36)+(y^2+8y+16)=100

Factor

(x+6)^2+(y+4)^2=100

Solution: Standard form of a Circle.