What is the general form of the equation of a circle with a center at (7, 0) and a radius of 10?

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Answer 1 · 2015-11-12T23:26:37

$x^2 - 14x + y^2 - 51 = 0$

First, let's write the equation in standard form.

$(x - h)^2 + (y - k)^2 = r^2$

$=> (x - 7)^2 + (y - 0)^2 = 10^2$

$=> (x - 7)^2 + y^2 = 10^2$

Then, we expand the equation.

$=> (x^2 - 14x + 49) + y^2 = 100$

Finally, let's put all the terms in one side and simplify

$=> x^2 -14x + 49 + y^2 - 100 = 0$

$=> x^2 - 14x + y^2 - 51 = 0$