Question

How do you find the equation of the circle given Center: (3, -2); Radius: 3?

Answer 1

`(x - 3)^2 + (y +2)^2 = 9`

Explanation:

Standard equation of a circle `(x - h)^2 + (y - k)^2 = r^2`

`(h, k)` being center of the circle

`(x - 3)^2 + (y - (-2))^2 = 3^2`

`(x - 3)^2 + (y +2)^2 = 9`