The circle equation is
f(x,y)=(x-x_0)^2+(y-y_0)^2-r^2 in which x_0,y_0 are the circle coordinates and r the radius.
If the points p_1=(x_1,y_1), p_2=(x_2,y_2), p_3=(x_3,y_3)
obey the circle equation then
f(x_1,y_1) =f(x_2,y_2)=f(x_3,y_3)=0
or
{((x_1-x_0)^2+(y_1-y_0)^2-r^2 = 0),((x_2-x_0)^2+(y_2-y_0)^2-r^2 = 0),((x_3-x_0)^2+(y_3-y_0)^2-r^2 = 0):}
Subtracting the second from the first and the third from the second we have
{(2(x_2-x_1)x_0 + 2(y_2-y_1)y_0 +(x_1^2-x_2^2+y_1^2-y_2^2)=0),(2(x_3-x_2)x_0 + 2(y_3-y_2)y_0 +(x_2^2-x_3^2+y_2^2-y_3^2)=0):}
Solving for x_0,y_0 after substituting the values for x_1,y_1,x_2,x_2,x_3,y_3 we get
x_0=2,y_0=1.
The radius is found by solving for r
(x_1-x_0)^2+(y_1-y_0)^2-r^2 = 0 so r = 5 sqrt(2)
