How do you find the equation of the line perpendicular to y+5=3(x-2) that passes through the point (6, 2)?
2 Answers
Let,the equation of line be
Now,arranging the given equation in the above mentioned form to get its slope,
Given,
So,its slope is
Now,for two lines to be mutually perpendicular,their product of slope must be
So,
or.
So,our required line equation becomes,
Now,given,that the line passes through
So,
or,
So,the equation of the line is
or,
Or
Or
Or
Explanation:
There are several forms for the equation of a straight line:
Another is
where
This is exactly the form we have for the given equation:
If lines are perpendicular, the product of their slopes is
One is the negative reciprocal of the other, so:
Using
Or in another form:
Or even