How do you find the equation of the secant line through the points where X has the given values: #h(x)=sqrt(x-5)#; x=6, x=9?

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Answer 1 · 2015-10-26T18:53:42

A secant line is a line through two points on the curve.

Find the two points, then find the equation of the line through them.

#y = h(x) = sqrt(x-5)#

When #x=6#, we get #y = f(6) = sqrt((6)-5) = sqrt1 = 1#

One of the points is #(6,1)#

When #x=9#, we get #y = f(9) = sqrt((9)-5) = sqrt4 = 2#

One of the points is #(9,2)#

Find the equation through the points #(6,1)# and #(9,2)#.

I assume that the student can finish this.

You should get #y=1/3x-1#