How do you find the foci and sketch the hyperbola x^2-y^2=1x2y2=1?

1 Answer
Feb 10, 2018

(+-1,0)(±1,0) would be the foci

Explanation:

graph{x^2-y^2=1 [-10, 10, -5, 5]}

given equation of hyperbola, x^2−y^2=1x2y2=1

the general equation for hyperbolas with center at origin and foci on x axis is x^2/a^2−y^2/b^2=1x2a2y2b2=1, where the foci are (+-a'0)

therefore, the foci for, x^2−y^2=1 is, (+-1,0)