Question

How do you find the foci and sketch the hyperbola `x^2-y^2=1`?

Answer 1

`(+-1,0)` would be the foci

Explanation:

graph{x^2-y^2=1 [-10, 10, -5, 5]}

given equation of hyperbola, `x^2−y^2=1`

the general equation for hyperbolas with center at origin and foci on x axis is `x^2/a^2−y^2/b^2=1`, where the foci are `(+-a'0)`

therefore, the foci for, `x^2−y^2=1` is, `(+-1,0)`